} NCERT Solutions for Class 8th Maths Chapter 2 Linear Equations in One Variable - AJacademy NCERT Solutions for Class 8th Maths Chapter 2 Linear Equations in One Variable

NCERT Solutions for Class 8th Maths Chapter 2 Linear Equations in One Variable

 

NCERT Solutions for Class 8th Maths 



Chapter 2 Linear Equations in One Variable

Exercise  2.1 


Q1.Solve the equation: x – 2 = 7.
Sol:
Here: x – 2 = 7
⇒ x – 2 + 2 = 7 + 2 (adding 2 on both sides)
⇒ x = 9 (Required solution)

Q2.Solve the equation: y + 3 = 10.
Here: y + 3 = 10
⇒ y + 3 – 3 = 10 – 3 (subtracting 3 from each side)
⇒ y = 7 (Required solution)

Q3. Solve the equation: 6 = z + 2
Sol:
We have 6 = z + 2
⇒ 6 – 2 = z + 2 – 2 (subtracting 2 from each side)
⇒ 4 = z
Thus, z = 4 is the required solution.

Q4.Solve the equations: 37 + x = 177

Sol:
NCERT Solutions for Class 8 Maths Chapter 2 Linear Equations in One Variable Ex 2.1 Q4

Q5. Solve the equation 6x = 12.
Sol:
We have 6x = 12
⇒ 6x ÷ 6 = 12 ÷ 6 (dividing each side by 6)
⇒ x = 2
Thus, x = 2 is the required solution.

Q6.Solve the equation t5 = 10.
Sol:
Given t5 = 10
⇒ t5 × 5 = 10 × 5 (multiplying both sides by 5)
⇒ t = 50
Thus, t = 50 is the required solution.

Q7.Solve the equation 2x3 = 18.
Sol:
We have 2x3 = 18
⇒ 2x3 × 3 = 18 × 3 (multiplying both sides by 3)
⇒ 2x = 54
⇒ 2x ÷ 2 = 54 ÷ 2 (dividing both sides by 2)
⇒ x = 27
Thus, x = 27 is the required solution.

Q8.Solve the equation 1.6 = y1.5
Sol:
Given: 1.6 = y1.5
⇒ 1.6 × 1.5 = y1.5 × 1.5 (multiplying both sides by 1.5)
⇒ 2.40 = y
Thus, y = 2.40 is the required solution.

Q9. Solve the equation 7x – 9 = 16.
Sol:
We have 7x – 9 = 16
⇒ 7x – 9 + 9 = 16 + 9 (adding 9 to both sides)
⇒ 7x = 25
⇒ 7x ÷ 7 = 25 ÷ 7 (dividing both sides by 7)
⇒ x = 257
Thus, x = 257 is the required solution.

Q10. Solve the equation 14y – 8 = 13.
Sol:
We have 14y – 8 = 13
⇒ 14y – 8 + 8 = 13 + 8 (adding 8 to both sides)
⇒ 14y = 21
⇒ 14y ÷ 14 = 21 ÷ 14 (dividing both sides by 14)
⇒ y = 2114
⇒ y = 32
Thus, y = 32 is the required solution.

Q11. Solve the equation 17 + 6p = 9.
Sol:
We have, 17 + 6p = 9
⇒ 17 – 17 + 6p = 9 – 17 (subtracting 17 from both sides)
⇒ 6p = -8
⇒ 6p ÷ 6 = -8 ÷ 6 (dividing both sides by 6)
⇒ p = 86
⇒ p = 43
Thus, p = 43 is the required solution.

Q12. Solve the equation x3 + 1 = 715
Sol:

NCERT Solutions for Class 8 Maths Chapter 2 Linear Equations in One Variable Ex 2.1 Q12

NCERT Solutions for Class 8 Maths Chapter 2 Linear Equations in One Variable Ex 2.1 Q12.1

Ncert solution 8th Maths.

Like and share on Facebook.


views

Post a Comment

0 Comments

Indian History